The Honor Spren she/her Posted May 26, 2017 Report Share Posted May 26, 2017 Spoiler 0 Quote Link to comment Share on other sites More sharing options...
The Sovereign Posted May 26, 2017 Report Share Posted May 26, 2017 And a long weekend...! 2 Quote Link to comment Share on other sites More sharing options...
Sunbird she/her Posted May 26, 2017 Report Share Posted May 26, 2017 @Darkness Ascendant unfortunately it was too dark for photos. Didn't help that I left my camera at home. XD 0 Quote Link to comment Share on other sites More sharing options...
Truthweaver she/her Posted May 26, 2017 Report Share Posted May 26, 2017 I almost got my mom to watch the Harry Potter movies by telling her she could see Violet Crawley brandish a stick and utter gibberish. 2 Quote Link to comment Share on other sites More sharing options...
The Sovereign Posted May 26, 2017 Report Share Posted May 26, 2017 1 hour ago, Truthweaver said: I almost got my mom to watch the Harry Potter movies by telling her she could see Violet Crawley brandish a stick and utter gibberish. Maggie Smith is excellent leverage. 1 Quote Link to comment Share on other sites More sharing options...
Silverblade5 he/him Posted May 26, 2017 Report Share Posted May 26, 2017 On 5/25/2017 at 3:36 AM, Chaos said: At first this had me turn my head, but the answer to your question is simple: |x-1| and |1-x| are the same function. You see, when you integrate 1/x, the antiderivative is not ln(x), but actually ln|x|. That absolute value is important because now those two functions have the same domains. That is essential here because when you integrate 1/(x-1) you get ln|x-1|. But really, by looking ln(x-1) vs. ln(1-x) they are the same function except for some domain issues. The absolute values fix that. ln|x-1| contains those smaller domained functions. Basically those two functions are the two halves of ln|x-1|. Of course, if you use Wolfram Alpha plotting you'll see that their graph of their real part (if you allow complex solutions) are exactly the same: http://www.wolframalpha.com/input/?i=y+%3D+ln(x-1) http://www.wolframalpha.com/input/?i=y+%3D+ln(1-x) How would I apply this in a differential equation? For example, if I had the equation dx/ab = (1/(ac - y)) dy, the first step to solving would be to integrate both sides, which would result in x/ab + C = -ln|ac - y|. How would I deal with this absolute value when trying to isolate y? 0 Quote Link to comment Share on other sites More sharing options...
The Honor Spren she/her Posted May 26, 2017 Report Share Posted May 26, 2017 Person: I know you're trying to relearn piano, but can you stop badly playing so much Nintendo soundtrack? Me: Spoiler 4 Quote Link to comment Share on other sites More sharing options...
Sunbird she/her Posted May 27, 2017 Report Share Posted May 27, 2017 Have you guys seen the winning entries to the First Annual Comedy Wildlife Photography Awards? They are, naturally, hilarious, so much so that I've started making memes out of some of them... Spoilered for size. Spoiler Spoiler Spoiler 4 Quote Link to comment Share on other sites More sharing options...
StrikerEZ he/him Posted May 27, 2017 Report Share Posted May 27, 2017 So, I was in the shower, and I came up with something. Branderson. When you're too lazy to say Brandon Sanderson, but don't want to just say Brandon or Sanderson. 0 Quote Link to comment Share on other sites More sharing options...
A Budgie she/her Posted May 27, 2017 Report Share Posted May 27, 2017 41 minutes ago, StrikerEZ said: So, I was in the shower, and I came up with something. Branderson. When you're too lazy to say Brandon Sanderson, but don't want to just say Brandon or Sanderson. Well, one of my friends called him Brand Sand and Brando Sando once so it could be worse. @Sunbirb those are great. My school's music office has the three headed giraffe one on their noticeboard, with the caption 'alien giraffe.' 0 Quote Link to comment Share on other sites More sharing options...
A Budgie she/her Posted May 27, 2017 Report Share Posted May 27, 2017 Double posting because I just saw this:https://twitter.com/SupanovaExpo/status/863253190891847680/photo/1 Brandon Sanderson is coming to Perth. Perth. And in case you didn't realise, that's where I live.I could go meet Sanderson... 5 Quote Link to comment Share on other sites More sharing options...
Jedal he/him Posted May 27, 2017 Report Share Posted May 27, 2017 This is both touching and absolutely hilarious at the same time. Warning for explicit language. https://youtu.be/yvxQGPAc5Rs 0 Quote Link to comment Share on other sites More sharing options...
firstRainbowRose she/her Posted May 28, 2017 Report Share Posted May 28, 2017 It's time for another Jackbox stream of Josh, Wilson and I! Twitch.tv/basstrace. We would love an audience! edit: Done for the night. 0 Quote Link to comment Share on other sites More sharing options...
Oversleep Posted May 28, 2017 Report Share Posted May 28, 2017 (edited) I already posted it in Math & Science thread but I figure more people frequent this one... Edited May 28, 2017 by Oversleep 0 Quote Link to comment Share on other sites More sharing options...
Exalted Posted May 28, 2017 Report Share Posted May 28, 2017 7 hours ago, Oversleep said: I already posted it in Math & Science thread but I figure more people frequent this one... ...one hour later, when I should probably have been doing homework or something useful: Spoiler The best I can come up with is "no, you can't". 0 Quote Link to comment Share on other sites More sharing options...
Steelborn he/him Posted May 28, 2017 Report Share Posted May 28, 2017 Hey guys check out the new Mistborn trailer HERE 5 Quote Link to comment Share on other sites More sharing options...
Mestiv he/him Posted May 28, 2017 Report Share Posted May 28, 2017 11 minutes ago, Steelborn said: Hey guys check out the new Mistborn trailer HERE Nice one! 0 Quote Link to comment Share on other sites More sharing options...
Sunbird she/her Posted May 29, 2017 Report Share Posted May 29, 2017 I thought this photo of an apparently headless Cooper's Hawk would amuse y'all: Spoiler He was preening his back feathers; here's what he looks like normally XD Spoiler Random side note: @Mestiv, your sig has nailed down my city but failed to notice that my display name is now Sunbirb, not Sunbird. 2 Quote Link to comment Share on other sites More sharing options...
Elenion he/him Posted May 29, 2017 Report Share Posted May 29, 2017 On 05/26/2017 at 4:43 PM, Silverblade5 said: How would I apply this in a differential equation? For example, if I had the equation dx/ab = (1/(ac - y)) dy, the first step to solving would be to integrate both sides, which would result in x/ab + C = -ln|ac - y|. How would I deal with this absolute value when trying to isolate y? My knowledge of calculus doesn't extend far, but I'll share what I've got: The shortcut here is, if you have a point on f(x), "initial condition" is what my teacher called it, to plug in that (x,y) pair into the half-solved differential equation and see if the term inside the absolute value is positive or negative. If it is positive, you can drop the absolute value, because it isn't necessary to find the solution. If the absolute value ends up containing a negative value, multiply the interior of the absolute value by -1 and then drop the absolute value bars. It's the same sort of thing that you have to do with the square root when you're solving a differential equation whose result is a circle and you need to determine whether or not you need the top or bottom half of it. If you don't have an initial condition, I can't help you too much. My course didn't cover that. Maybe define a piecewise function based on y being less than or greater than ac? [\CrazyMathStuff] 0 Quote Link to comment Share on other sites More sharing options...
Elenion he/him Posted May 29, 2017 Report Share Posted May 29, 2017 19 hours ago, Oversleep said: I already posted it in Math & Science thread but I figure more people frequent this one... 12 hours ago, Exalted Dungeon Master said: ...one hour later, when I should probably have been doing homework or something useful: Reveal hidden contents The best I can come up with is "no, you can't". (I don't want to deal with that quoting into edits glitch, so double-post it is) Brute-force algebra has failed me, so I've attacked this one with critical thinking, and here's what I've got so far: (A, B, and C could be any of the fruits; the problem doesn't change whether A is apple or banana or pineapple, etc) IF a solution exists with the specified domain restrictions: A > B >= C A > (B + C) A > 6 A, B, and C are either all odd numbers or all even numbers And, with a little help from an online graphing calculator, I can say that none of A, B, or C = 0. That's all the time I've got right now. 0 Quote Link to comment Share on other sites More sharing options...
Darkness Ascendant he/him Posted May 29, 2017 Report Share Posted May 29, 2017 1 Quote Link to comment Share on other sites More sharing options...
A Budgie she/her Posted May 29, 2017 Report Share Posted May 29, 2017 @Darkness Ascendant that's a cool little thing. The colour representation was interesting as well, because it didn't really tell you much- it's ambigious and not clearly defined, just like the subject it's talking about. 0 Quote Link to comment Share on other sites More sharing options...
ParadoxicalZen he/him Posted May 29, 2017 Report Share Posted May 29, 2017 @Darkness Ascendant *preach/hallelujah emoji* major props for this program 0 Quote Link to comment Share on other sites More sharing options...
Erunion he/him Posted May 29, 2017 Report Share Posted May 29, 2017 @Oversleep - That's 1 equation and 3 unknowns, which means you cannot get a unique algebraic solution. That doesn't mean it's insoluble, just that the solution won't be unique, and you can't use standard algebraic methods. In other words, it would take a loooot of time, or a really lucky guess. 0 Quote Link to comment Share on other sites More sharing options...
Oversleep Posted May 29, 2017 Report Share Posted May 29, 2017 (edited) 9 minutes ago, Erunion said: @Oversleep - That's 1 equation and 3 unknowns, which means you cannot get a unique algebraic solution. That doesn't mean it's insoluble, just that the solution won't be unique, and you can't use standard algebraic methods. I know The whole thing is a very elaborate trolling. Spoiler The "95% of people cannot solve it" is actually true. One solution is x = 4373612677928697257861252602371390152816537558161613618621437993378423467772036; y = 6875131794129999827197811565225474825492979968971970996283137471637224634055579; z = 154476802108746166441951315019919837485664325669565431700026634898253202035277999here is explanation Edited May 29, 2017 by Oversleep 2 Quote Link to comment Share on other sites More sharing options...
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